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Title: Gaplessness of half-integer spin Heisenberg chains with $S \ge 3/2$
Plain: Chains of half-integer spins are expected to have no energy gap. A general theorem allows either no gap or several ground states, and only the spin-1/2 case is solved exactly.
Precise: For $H = \sum_i S_i . S_{i+1}$ with $S = 3/2$ (or any half-integer $S \ge 3/2$), prove that $E_1(L) - E_0(L) \to 0$ as $L \to \infty$ with a unique ground state, or equivalently exclude dimerization. The Lieb-Schultz-Mattis theorem (and Affleck-Lieb extension) gives gapless or degenerate. Answer: a proof.
Settled by: A proof that the $S = 3/2$ chain is gapless with a unique ground state.
Kind: well-posed
Answer type: proof
References: (empty)
Literature status: open
Status note: (empty)
Posed since: 1983