Two-nucleon binding from lattice QCD at physical quark masses · revision history
Revision 1
Accepted · first revision · record
- Title
- Two-nucleon binding from lattice QCD at physical quark masses
- Plain
- The deuteron (a bound proton and neutron) is held together by only 2.2 MeV, while two neutrons do not bind at all. Lattice QCD calculations at heavier-than-real quark masses disagree with each other on whether two nucleons bind.
- Precise
- Compute the $I=0$ (deuteron) and $I=1$ (dineutron) S-wave nucleon-nucleon phase shifts and pole positions in lattice QCD at the physical pion mass, with continuum and infinite-volume extrapolation. Answer: deuteron binding energy (experiment $2.2246\,\mathrm{MeV}$) and the $1S0$ nn scattering length (experiment about $-18.9\,\mathrm{fm}$), plus resolution of the dependence of results on the choice of interpolating operators found at $m_{\pi}$ above $300\,\mathrm{MeV}$.
- Settled by
- Variational lattice QCD spectra with complete two-nucleon operator bases at several pion masses down to physical, converted to scattering amplitudes with the Luscher finite-volume method (which maps energies in a finite box to phase shifts).
- Kind
- well-posed
- Answer type
- value
- References
- (empty)
- Literature status
- contested
- Status note
- A 2025 calculation with a large operator basis at $m_{\pi}$ about $714\,\mathrm{MeV}$ found no bound dinucleons (BaSc collaboration, arXiv 2505.05547), contradicting earlier deep-binding results obtained with compact hexaquark operators.
- Posed since
- (empty)